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首页 / 操作系统 / Linux / 让GCC支持成员函数模板的trick

gcc 4.7.3 不支持成员函数模板特化。如下代码:#ifndef __MEMFUNTEMPLATE_H__
#define __MEMFUNTEMPLATE_H__
#include <stdio.h>
class Base {};
class Derived : public Base {};
struct Functor {
    template <typename T> void function() {
        printf(" Primary template. ");
    }
    template<>
    void function<int>(){
        printf(" Specialization for int. ");
    }
    template<> void function<Base *>() {
        printf(" Specialization for Base *. ");
    }
};
class Tester {
public:
    static void DoTest()
    {
        Functor functor;
        functor.function<char>();
        functor.function<int>();
        functor.function<Base *>();
        functor.function<Derived *>();
    }
};
#endif // __MEMFUNTEMPLATE_H__
在 VS2010 中编译运行是没有问题的,但在 gcc 4.7.3下,编译都通不过:
../src/MemFunTemplate.h:21:14: error: <strong>explicit specialization in non-namespace scope</strong> ‘struct Functor’
../src/MemFunTemplate.h:22:24: error: template-id ‘function<int>’ in declaration of primary template
../src/MemFunTemplate.h:26:14: error: explicit specialization in non-namespace scope ‘struct Functor’
../src/MemFunTemplate.h:26:38: error: template-id ‘function<Base*>’ in declaration of primary template
../src/MemFunTemplate.h:26:21: error: ‘void Functor::function()’ cannot be overloaded
../src/MemFunTemplate.h:22:10: error: with ‘void Functor::function()’
../src/MemFunTemplate.cpp: In function ‘int main()’:
../src/MemFunTemplate.cpp:17:2: error: ‘DoTest’ is not a member of ‘Functor’为了达到近似成员函数模板特化的效果,可以利用成员函数主模板以及重载函数来实现: 
/*
 * MemFunTemplate.h
 *
 *  Created on: Jul 12, 2013
 *      Author: www.linuxidc.com
 */
#ifndef MEMFUNTEMPLATE_H_
#define MEMFUNTEMPLATE_H_
#include <stdio.h>
template<typename T>
struct DummyIdentity {
    typedef T type;
};
class Base {};
class Derived : public Base {};
struct Functor {
    template <typename T> void function() {
        function(DummyIdentity<T>());
    }
private:
    template <typename T>
    void function(DummyIdentity<T>) {
        printf(" Primary template DummyIdentity<T>. ");
    }
    void function(DummyIdentity<int>) {
        printf(" overload function for DummyIdentity<int>. ");
    }
    void function(DummyIdentity<Base *>) {
        printf(" overload function for DummyIdentity<Base *>. ");
    }
};
class Tester {
public:
    static void DoTest()
    {
        Functor functor;
        functor.function<char>();
        functor.function<int>();
        functor.function<Base *>();
        functor.function<Derived *>();
    }
};
#endif /* MEMFUNTEMPLATE_H_ */调用 DoTest() 运行结果如下: Primary template DummyIdentity<T>.
 overload function for DummyIdentity<int>.
 overload function for DummyIdentity<Base *>.
 Primary template DummyIdentity<T>.注意:VS2010 版本的代码,模板形参为 T,在实例化不会进行隐式类型转换。即用 Derived * 当作实参调用的是主模板,而不是 Base * 特化版本而在 gcc  下,模板形参虽然也为T,但影响重载决议的 function 参数为:DummyIdentity<T>,用不同的实际参数实例化该模板,得到的是一堆重载函数。因此用 Derived * 当作实参时,调用的函数自然就是实例化的 void function(DummyIdentity<T>)了。Linux升级GCC 4.8.1清晰简明教程(Ubuntu 12.04 64位版为例)  http://www.linuxidc.com/Linux/2014-04/99583.htm Ubuntu下Vim+GCC+GDB安装及使用 http://www.linuxidc.com/Linux/2013-01/78159.htm Ubuntu下两个GCC版本切换 http://www.linuxidc.com/Linux/2012-10/72284.htm CentOS6.5升级手动安装GCC4.8.2  http://www.linuxidc.com/Linux/2015-01/112595.htm GCC 的详细介绍:请点这里本文永久更新链接地址:http://www.linuxidc.com/Linux/2016-03/129085.htm