//1.输入一个字节内的数(0-255),然后将该数的转换为二进制数,然后将高四位和第四位互换// int a = 0;// printf("请输入一个(0-255)字节内的的数:
");// scanf("%d", &a);// unsigned char c = (unsigned char)a;// unsigned char left = 0;//存储左移之后的结果// unsigned char right = 0;//存储右移之后的结果// left = c << 4;// right = c >> 4;// printf("%d
", left | right); //2.输入一个字节内的整数(0-255),然后将该数的转换为二进制数,然后将奇数位和偶数位互换// int a = 0;// printf("请输入一个(0-255)字节内的数:
");// scanf("%d", &a);// unsigned char c = (unsigned char)a;// unsigned char left = 0;//存储左移之后的结果// unsigned char right = 0;//存储右移之后的结果// left = c << 1;// left = left & 170;// right = c >> 1;// right = right & 85;// unsigned char result = left | right;// printf("%d", result); //3.输入一个字节内的数(0-255)和移动位数.输出移位结果(要求循环移位) //提示:系统自带的移位都是非循环的// int a = 0, b = 0;// printf("请输入一个(0 - 255)字节内的数和移动位数:
");// scanf("%d%d", &a, &b);// unsigned char c = (unsigned char)a;// unsigned char left = 0; //存储左移之后的结果// unsigned char right = 0; //存储右移之后的结果// left = c << b;// right = c >> (8 - b);// printf("%d
", left | right);百度2013校园招聘笔试题 http://www.linuxidc.com/Linux/2013-01/78272.htm百度2013校园招聘研发面经 http://www.linuxidc.com/Linux/2012-11/74057.htm2012百度实习生招聘面试题 http://www.linuxidc.com/Linux/2012-10/73240.htm百度2011.10.16校园招聘会笔试题 http://www.linuxidc.com/Linux/2012-10/72976.htm百度2012实习生校园招聘笔试题 http://www.linuxidc.com/Linux/2012-10/72413.htm百度垂直搜索部门实习面经 http://www.linuxidc.com/Linux/2012-10/72412.htm百度2014校园招聘笔试题(长沙站) http://www.linuxidc.com/Linux/2013-10/90817.htm百度2014校园招聘算法 http://www.linuxidc.com/Linux/2014-05/102526.htm本文永久更新链接地址:http://www.linuxidc.com/Linux/2014-07/104761.htm