Django 查询时间段大于某个时间
gtnow = datetime.datetime.now()
start = now – datetime.timedelta(hours=23, minutes=59, seconds=59)
a=yourobject.objects .filter(youdatetimcolumn__gt=start)
[, , ]
大于等于某个时间:
gte查询的时候用
a=yourobject.objects .filter(youdatetimcolumn__gte=start)
语法
小于:lta=yourobject.objects .filter(youdatetimcolumn__lt=start)小于等于
ltea=yourobject.objects .filter(youdatetimcolumn__lte=start)查询时间段rangestart_date = datetime.date(2005, 1, 1)
end_date = datetime.date(2005, 3, 31)
Entry.objects.filter(pub_date__range=(start_date, end_date))查询某年:
year
Entry.objects.filter(pub_date__year=2005)
查询某月:monthEntry.objects.filter(pub_date__month=12)某天
dayEntry.objects.filter(pub_date__day=3)星期几
week_dayFoEntry.objects.filter(pub_date__week_day=2)