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用Python实现一个简单的算术游戏:#!/usr/bin/env pythonfrom operator import add, sub
from random import randint, choiceops = {"+": add, "-":sub}
#定义一个字典
MAXTRIES = 2def doprob():
op = choice("+-")
#用choice从"+-"中随意选择操作符
nums = [randint(1,10) for i in range(2)]
#用randint(1,10)随机生成一个1到10的数,随机两次使用range(2)
nums.sort(reverse=True)
#按升序排序
ans = ops[op](*nums)
#利用函数
pr = "%d %s %d = " % (nums[0], op, nums[1])
oops = 0
#oops用来计算failure测试,当三次时自动给出答案
while True:
try:
if int(raw_input(pr)) == ans:
print "correct"
break
if oops == MAXTRIES:
print "answer
%s%d" % (pr, ans)
break
else:
print "incorrect... try again"
oops += 1
except (KeyboardInterrupt, EOFError, ValueError):
print "invalid ipnut... try again"
def main():
while True:
doprob()
try:
opt = raw_input("Again? [y]").lower()
if opt and opt[0] == "n":
break
except (KeyboardInterrupt, EOFError):
breakif __name__ == "__main__":
main()