IT 面试中,数据库的相关问题基本上属于必考问题,而其中关于sql语句也是经常考察的一个重要知识点。下面介绍下sql语句中一个比较重要的操作group by,他的重要行一方面体现在他的理解困难度,一方面体现应用中的长见性。--------------------------------------分割线 --------------------------------------Ubuntu 14.04下安装MySQL http://www.linuxidc.com/Linux/2014-05/102366.htm《MySQL权威指南(原书第2版)》清晰中文扫描版 PDF http://www.linuxidc.com/Linux/2014-03/98821.htmUbuntu 14.04 LTS 安装 LNMP NginxPHP5 (PHP-FPM)MySQL http://www.linuxidc.com/Linux/2014-05/102351.htmUbuntu 14.04下搭建MySQL主从服务器 http://www.linuxidc.com/Linux/2014-05/101599.htmUbuntu 12.04 LTS 构建高可用分布式 MySQL 集群 http://www.linuxidc.com/Linux/2013-11/93019.htmUbuntu 12.04下源代码安装MySQL5.6以及Python-MySQLdb http://www.linuxidc.com/Linux/2013-08/89270.htmMySQL-5.5.38通用二进制安装 http://www.linuxidc.com/Linux/2014-07/104509.htm--------------------------------------分割线 --------------------------------------首先,给出一个studnet学生表: CREATE TABLE `student` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(30) DEFAULT NULL,
`sex` tinyint(1) DEFAULT "0",
`score` int(10) NOT NULL,
`dept` varchar(10) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=8 DEFAULT CHARSET=utf8添加一些测试数据:mysql> select * from student where id<10;
+----+------+------+-------+---------+
| id | name | sex | score | dept |
+----+------+------+-------+---------+
| 1 | a | 1 | 90 | dev |
| 2 | b | 1 | 90 | dev |
| 3 | b | 0 | 88 | design |
| 4 | c | 0 | 60 | sales |
| 5 | c | 0 | 89 | sales |
| 6 | d | 1 | 100 | product |
+----+------+------+-------+---------+给出需求,写出sql:给出各个部门最高学生的分数。要想得到各个部门学生,首先就要分组,按照部门把他们分组,然后在各个部门中找到分数最高的就可以了。所以sql语句为:mysql> select *, max(score) as max from student group by dept order by name;
+----+------+------+-------+---------+------+
| id | name | sex | score | dept | max |
+----+------+------+-------+---------+------+
| 1 | a | 1 | 90 | dev | 90 |
| 3 | b | 0 | 88 | design | 88 |
| 4 | c | 0 | 60 | sales | 89 |
| 6 | d | 1 | 100 | product | 100 |
+----+------+------+-------+---------+------+
4 rows in set (0.00 sec)这只是个简单的例子,我们可以再把这个例子复杂化,比如分数最高的必须是女生,即sex列值必须为1才挑选出,这时的sql语句应该为:mysql> select *,max(score) as max from student group by dept having sex="1" order by name;
+----+------+------+-------+---------+------+
| id | name | sex | score | dept | max |
+----+------+------+-------+---------+------+
| 1 | a | 1 | 90 | dev | 90 |
| 6 | d | 1 | 100 | product | 100 |
+----+------+------+-------+---------+------+
2 rows in set (0.46 sec)这里我们没有用where语句而是用了having,这里简单说明一下,因为我们的条件是在分组后进行的,其实分组前挑选出sex="1",然后再按照dept部门分组,也是可行的,这里就要看题目是怎么要求的:mysql> select *,max(score) as max from student where sex="1" group by dept order by name;
+----+------+------+-------+---------+------+
| id | name | sex | score | dept | max |
+----+------+------+-------+---------+------+
| 1 | a | 1 | 90 | dev | 90 |
| 6 | d | 1 | 100 | product | 100 |
+----+------+------+-------+---------+------+
2 rows in set (0.05 sec)
更多详情见请继续阅读下一页的精彩内容: http://www.linuxidc.com/Linux/2014-08/105216p2.htm
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