操作方法Dict = {"a":1,"b":2,"c":3,"d":4} Dict.has_key(key) 判断一个字典是否有某个key>>> Dict.has_key("b")True>>> Dict.has_key("e")False Dict.keys() 获得一个字典所有的key,存入一个list中>>> Dict.keys()["a","b","c","d"] Dict.values() 获得一个字典所有的value,存入一个list中[1,2,3,4] Dict.copy() 将一个Dict拷贝给另一个Dict,而不是传索引>>> Dict_1 = Dict.copy()>>> Dict_1["a"] = 0>>> Dict_1,Dict{"a":0,"b":2,"c":3,"d":4},{"a":1,"b":2,"c":3,"d":4}如果是Dict_1 = Dict 那么任意dict改变之后,另外一个也会改变,=号赋值是引用传递 Dict.get(key, default) 获得指定key的值,如果没有值,返回default值>>> Dict.get("a")0>>> Dict.get("e",100)100 Dict.update(Dict_1) 遍历Dict_1来更新Dict ( PS: 类似与jQuery中的 p = $.extend({....},p); )help(Dict.update)的内容如下:update(...) D.update(E, **F) -> None. Update D from dict/iterable E and F. If E has a .keys() method, does: for k in E: D[k] = E[k] If E lacks .keys() method, does: for (k, v) in E: D[k] = v In either case, this is followed by: for k in F: D[k] = F[k] >>> Dict_1 = Dict.copy()>>> Dict_1["e"] = 100>>> Dict_1["a"] = -1>>> Dict,Dict_1{"a":1,"b":2,"c":3,"d":4},{"a":-1,"b":2,"c":3,"d":4,"e":100} >>> Dict.update(Dict_1)>>> Dict{"a":-1,"b":2,"c":3,"d":4,"e":100}