Codeforces Round #205 (Div. 2) / 353C Find Maximum (贪心)2014-10-02 synapse7 Valera has array a, consisting of n integers a0,a1,...,an-1, and function f(x), taking an integer from 0 to 2n-1 as its single argument. Value f(x) is calculated by formula

, where value bit(i) equals one if the binary representation of number xcontains a 1 on the i-th position, and zero otherwise.For example, if n=4 and x=11 (11=20+21+23), then f(x)=a0+a1+a3.Help Valera find the maximum of function f(x) among all x, for which an inequality holds: 0≤x≤m.InputThe first line contains integer n (1≤n≤105) — the number of array elements. The next line contains n space-separated integersa0,a1,...,an-1 (0≤ai≤104) — elements of array a.The third line contains a sequence of digits zero and one without spaces s0s1... sn-1 — the binary representation of number m. Numberm equals

.OutputPrint a single integer — the maximum value of function f(x) for all

.Sample test(s)
input2
3 8
10output3input5
17 0 10 2 1
11010output27NoteIn the first test case m=20=1,f(0)=0,f(1)=a0=3.In the second sample m=20+21+23=11, the maximum value of function equals f(5)=a0+a2=17+10=27.本文URL地址:http://www.bianceng.cn/Programming/sjjg/201410/45352.htm思路:从左往右读,读到0就积累,读到1的时候,就看是修改这个1为0然后把前面的0改为1更大,还是不变更大。修改的话,就从当前这个修改成0的1开始积累。最终修改结果就是我们想要的x。完整代码:
/*62ms,500KB*/#include<cstdio>#include<algorithm>using namespace std;const int maxm = 100005;int a[maxm];char s[maxm];int main(){int n, sum, maxn, i;scanf("%d", &n);for (i = 0; i < n; ++i)scanf("%d", &a[i]);getchar();gets(s);sum = maxn = 0;for (i = 0; i < n; ++i){if (s[i] & 15){///看是前面的一串0大,还是当前位置的1大if (maxn > a[i]){sum += maxn;maxn = a[i]; ///重新积累}else sum += a[i];}else maxn += a[i];///积累maxn}printf("%d
", sum);return 0;}