POJ 2105 IP Address （strtoll函数）

POJ 2105 IP Address （strtoll函数）2014-07-30 csdn博客 synapse7Time Limit: 1000MS

Memory Limit: 30000K

Description

Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of "1s" and "0s" （bits） to a dotted decimal format. A dotted decimal format for an IP address is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the first 8 positions of the binary systems are:

27 26252423 222120 128 6432168 4 2 1

Input

The input will have a number N （1<=N<=9） in its first line representing the number of streams to convert. N lines will follow.

Output

The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.

Sample Input

400000000000000000000000000000000 00000011100000001111111111111111 11001011100001001110010110000000 01010000000100000000000000000001

Sample Output

0.0.0.03.128.255.255203.132.229.12880.16.0.1

Source

México and Central America 2004

这题可以直接算，也可以用一个cstdlib中的strtoll函数搞定

完整代码：

/*0ms,408KB*/#include<cstdio>#include<cstdlib>char str[40];int ip[4];int main（）{char* stopstr;__int64 num;int t, i;scanf（"%d
", &t）;while （t--）{gets（str）;num = strtoll（str, &stopstr, 2）;for （i = 3; i >= 0; --i）{ip[i] = num % 256;num >>= 8;}printf（"%d.%d.%d.%d
", ip[0], ip[1], ip[2], ip[3]）;}return 0;}