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UVa 10375 Choose and divide (组合数相除)2014-07-2410375 - Choose and divide

Time limit: 3.000 seconds

http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=115&page=show_problem&problem=1316

The binomial coefficient C(m,n) is defined as

        m!

C(m,n) = --------

        n!(m-n)!

Given four natural numbers p, q, r, and s, compute the the result of dividing C(p,q) by C(r,s).

The Input

Input consists of a sequence of lines. Each line contains four non-negative integer numbers giving values for p, q, r, and s, respectively, separated by a single space. All the numbers will be smaller than 10,000 with p>=q and r>=s.

The Output

For each line of input, print a single line containing a real number with 5 digits of precision in the fraction, giving the number as described above. You may assume the result is not greater than 100,000,000.

Sample Input

10 5 14 9

93 45 84 59

145 95 143 92

995 487 996 488

2000 1000 1999 999

9998 4999 9996 4998

Output for Sample Input

0.12587

505606.46055

1.28223

0.48996

2.00000

3.99960

思路:不要被题目那个公式误导了~自己算一算几个组合数,比如C(100,4),发现分子分母都是4个乘数,那就好办了,写一个for循环每次一除一乘就是。

完整代码:

/*0.022s*/#include<cstdio>#include<algorithm>using namespace std;int main(){int p, q, r, s,maxn,i;double ans;while (~scanf("%d%d%d%d", &p, &q, &r, &s)){q = max(q, p - q), s = max(s, r - s);maxn = max(q, s);ans = 1.0;for (i = 1; i <= maxn; ++i){if (i <= q) ans = ans / i * (p - q + i);if (i <= s) ans = ans / (r - s + i) * i;}printf("%.5f
", ans);}return 0;}
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