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POJ 1979 Red and Black (DFS)2014-07-24Time Limit: 1000MS

Memory Limit: 30000K

Description

There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can"t move on red tiles, he can move only on black tiles.

Write a program to count the number of black tiles which he can reach by repeating the moves described above.

Input

The input consists of multiple data sets. A data set starts with a line containing two positive integers W and H; W and H are the numbers of tiles in the x- and y- directions, respectively. W and H are not more than 20.

There are H more lines in the data set, each of which includes W characters. Each character represents the color of a tile as follows.

"." - a black tile

"#" - a red tile

"@" - a man on a black tile(appears exactly once in a data set)

The end of the input is indicated by a line consisting of two zeros.

Output

For each data set, your program should output a line which contains the number of tiles he can reach from the initial tile (including itself).

Sample Input

6 9

....#.

.....#

......

......

......

......

......

#@...#

.#..#.

11 9

.#.........

.#.#######.

.#.#.....#.

.#.#.###.#.

.#.#..@#.#.

.#.#####.#.

.#.......#.

.#########.

...........

11 6

..#..#..#..

..#..#..#..

..#..#..###

..#..#..#@.

..#..#..#..

..#..#..#..

7 7

..#.#..

..#.#..

###.###

...@...

###.###

..#.#..

..#.#..

0 0

Sample Output

45

59

6

13

Source

Japan 2004 Domestic

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完整代码:

/*16ms,388KB*/#include<cstdio>#include<cstring>char grid[25][25];bool vis[25][25];int cnt, x, y;void dfs(int i, int j){if (grid[i][j] == "#" || vis[i][j]) return;vis[i][j] = true;++cnt;dfs(i - 1, j); dfs(i + 1, j); dfs(i, j - 1); dfs(i, j + 1);}int main(){int i, j, xx, yy;while (scanf("%d%d
", &x, &y), x){memset(grid, "#", sizeof(grid));for (i = 1; i <= y; ++i){for (j = 1; j <= x; ++j){grid[i][j] = getchar();if (grid[i][j] == "@")xx = i, yy = j;}getchar();}memset(vis, 0, sizeof(vis));cnt = 0;dfs(xx, yy);printf("%d
", cnt);}return 0;}
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