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高精度运算类bign:支持前导零输入2014-07-22 synapse7 目前的缺陷:只能计算无符号数。

另:修改成C的输入输出的版本。

#include<cstdio>#include<cstring>#include<iostream>using namespace std;const int maxn = 200;struct bign{int len, s[maxn];bign(){memset(s, 0, sizeof(s));len = 1;}bign(int num){*this = num;}bign(const char* num){*this = num;}bign operator = (const int num){char s[maxn];sprintf(s, "%d", num);*this = s;return *this;}bign operator = (const char* num){len = strlen(num);for (int i = 0; i < len; i++) s[i] = num[len - i - 1] & 15;return *this;}string str() const{string res = "";for (int i = 0; i < len; i++) res = (char)(s[i] + "0") + res;if (res == "") res = "0";return res;}///去前导零void clean(){while (len > 1 && !s[len - 1]) len--;}///加bign operator + (const bign& b) const{bign c;c.len = 0;for (int i = 0, g = 0; g || i < max(len, b.len); i++){int x = g;if (i < len) x += s[i];if (i < b.len) x += b.s[i];c.s[c.len++] = x % 10;g = x / 10;}return c;}///减bign operator - (const bign& b) const{bign c;c.len = 0;for (int i = 0, g = 0; i < len; i++){int x = s[i] - g;if (i < b.len) x -= b.s[i];if (x >= 0) g = 0;else{g = 1;x += 10;}c.s[c.len++] = x;}c.clean();return c;}///乘bign operator * (const bign& b) const{bign c;c.len = len + b.len;for (int i = 0; i < len; i++)for (int j = 0; j < b.len; j++)c.s[i + j] += s[i] * b.s[j];for (int i = 0; i < c.len - 1; i++){c.s[i + 1] += c.s[i] / 10;c.s[i] %= 10;}c.clean();return c;}///除bign operator / (const bign& b) const{bign ret, cur = 0;ret.len = len;for (int i = len - 1; i >= 0; i--){cur = cur * 10;cur.s[0] = s[i];while (cur >= b){cur -= b;ret.s[i]++;}}ret.clean();return ret;}///模、余bign operator % (const bign& b) const{bign c = *this / b;return *this - c * b;}bool operator < (const bign& b) const{if (len != b.len) return len < b.len;for (int i = len - 1; i >= 0; i--)if (s[i] != b.s[i]) return s[i] < b.s[i];return false;}bool operator > (const bign& b) const{return b < *this;}bool operator <= (const bign& b) const{return !(b < *this);}bool operator >= (const bign& b) const{return !(*this < b);}bool operator == (const bign& b) const{return !(b < *this) && !(*this < b);}bool operator != (const bign& b) const{return b < *this || *this < b;}bign operator += (const bign& a){*this = *this + a;return *this;}bign operator -= (const bign& a){*this = *this - a;return *this;}bign operator *= (const bign& a){*this = *this * a;return *this;}bign operator /= (const bign& a){*this = *this / a;return *this;}bign operator %= (const bign& a){*this = *this % a;return *this;}};istream& operator >> (istream& in, bign& x){string s;in >> s;x = s.c_str();return in;}ostream& operator << (ostream& out, const bign& x){out << x.str();return out;}int main(void){bign a;cin >> a;a += "500000000000000000000000000000000000";cout << a * 2 << endl;return 0;}