Welcome

首页 / 软件开发 / 数据结构与算法 / UVa 488 Triangle Wave (water ver.)

UVa 488 Triangle Wave (water ver.)2014-07-16 csdn博客 synapse7488 - Triangle Wave

Time limit: 3.000 seconds

http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=94&page=show_problem&problem=429

In this problem you are to generate a triangular wave form according to a specified pair of Amplitude and Frequency.

Input and Output

The input begins with a single positive integer on a line by itself indicating the number of the cases following, each of them as described below. This line is followed by a blank line, and there is also a blank line between two consecutive inputs.

Each input set will contain two integers, each on a separate line. The first integer is the Amplitude; the second integer is the Frequency.

For each test case, the output must follow the description below. The outputs of two consecutive cases will be separated by a blank line.

For the output of your program, you will be printing wave forms each separated by a blank line. The total number of wave forms equals the Frequency, and the horizontal ``height"" of each wave equals the Amplitude. The Amplitude will never be greater than nine.

The waveform itself should be filled with integers on each line which indicate the ``height"" of that line.

NOTE: There is a blank line after each separate waveform, excluding the last one.

Sample Input

132

Sample Output

122333221122333221
完整代码:

/*0.065s*/#include <cstdio>int main(void){int T, A, F;int i, j, k, l;scanf("%d", &T);for (i = 0; i < T; i++){if (i)putchar("
");scanf("%d%d", &A, &F);for (j = 0; j < F; j++){if (j)putchar("
");for (k = 0; k < A; k++){for (l = 0; l <= k; l++)putchar("1" + k);putchar("
");}for (k = A - 2; k >= 0; k--){for (l = 0; l <= k; l++)putchar("1" + k);putchar("
");}}}return 0;}