复制代码 代码如下:
select * from _test a left join _test b on a.id=b.id where a.level="20" and a.month="04" and b.level="20" and b.month="03";
select a.*,b.* from (select * from _test where level="20" and month="04") as a left join (select * from _test where level="20" and month="03") as b on a.id=b.id;
这两条语句结果是不同的,应该是left join的时候如果条件是多个表mysql会自动转成内联导致,第二条语句才能达到正确的目的(为了找到相差的两条数据)。
