创建测试表:
DROP TABLE IF EXISTS `test`;CREATE TABLE `test` (`year` int(11) DEFAULT NULL,`month` int(11) DEFAULT NULL,`amount` double DEFAULT NULL) ENGINE=InnoDB DEFAULT CHARSET=utf8;插入数据:
INSERT INTO `test` VALUES ("1991", "1", "1.1");INSERT INTO `test` VALUES ("1991", "2", "1.2");INSERT INTO `test` VALUES ("1991", "3", "1.3");INSERT INTO `test` VALUES ("1991", "4", "1.4");INSERT INTO `test` VALUES ("1992", "1", "2.1");INSERT INTO `test` VALUES ("1992", "2", "2.2");INSERT INTO `test` VALUES ("1992", "3", "2.3");INSERT INTO `test` VALUES ("1992", "4", "2.3");看到题目要求,仔细想想可以:
select year,sum(if(month=1,amount,0)) as "M1",sum(if(month=2,amount,0)) as "M2",sum(if(month=3,amount,0)) as "M3",sum(if(month=4,amount,0)) as "M4"from testGROUP by year;效果如下:
以上所述是小编给大家介绍的Mysql的列修改成行并显示数据的简单实现,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对脚本之家网站的支持!