首页 / 脚本样式 / JavaScript / JSON字符串转换JSONObject和JSONArray的方法

//JSONObjectString jsonMessage = "{"语文":"88","数学":"78","计算机":"99"}";String value1 = null;try{//将字符串转换成jsonObject对象JSONObject myJsonObject = new JSONObject（jsonMessage）;//获取对应的值value1 = myJsonObject.getString（"数学"）;}catch （JSONException e）{}System.out.println（"value1="+value1）;//JSONArrayjsonMessage = "[{"num":"成绩", "外语":88, "历史":65, "地理":99, "object":{"aaa":"1111","bbb":"2222","cccc":"3333"}}," +"{"num":"兴趣", "外语":28, "历史":45, "地理":19, "object":{"aaa":"11a11","bbb":"2222","cccc":"3333"}}," +"{"num":"爱好", "外语":48, "历史":62, "地理":39, "object":{"aaa":"11c11","bbb":"2222","cccc":"3333"}}]";JSONArray myJsonArray;try{myJsonArray = new JSONArray（jsonMessage）;for（int i=0 ; i < myJsonArray.length（） ;i++）{//获取每一个JsonObject对象JSONObject myjObject = myJsonArray.getJSONObject（i）;//获取每一个对象中的值String numString = myjObject.getString（"num"）;int englishScore = myjObject.getInt（"外语"）;int historyScore = myjObject.getInt（"历史"）;int geographyScore = myjObject.getInt（"地理"）;//获取数组中对象的对象JSONObject myjObject2 = myjObject.getJSONObject（"object"）;String aaaString = myjObject2.getString（"aaa"）;System.out.println（"aaaString="+aaaString）;System.out.println（"numString="+numString）;System.out.println（"englishScore="+englishScore）;System.out.println（"historyScore="+historyScore）;System.out.println（"geographyScore="+geographyScore）;}}catch （JSONException e）{}