<body><form action="fileUpload/fileUpload" method="post" enctype="multipart/form-data"><input type="text" name="password"><input type="file" name="file"><input type="text" name="username"><input type="submit" value="submit"></form><button id="button">提交</button></body>java代码(具体的springmvc配置,包括文件上传的配置参考http://www.jb51.net/article/84078.htm)
@Controller@RequestMapping("/fileUpload")public class FileUpload {@RequestMapping("/fileUpload")@ResponseBodypublic String FileUpload1(@RequestParam("file")MultipartFile file/*, @RequestParam("username")String username*/){System.out.println("------------------------------- "+ file.getSize());if(!file.isEmpty()){System.out.println("Process file: "+file.getOriginalFilename() );try {FileUtils.copyInputStreamToFile(file.getInputStream(), new File("c:\temp\imooc\", System.currentTimeMillis()+ file.getOriginalFilename()));} catch (IOException e) {e.printStackTrace();}}return "NewFile";}} 2. 使用jquery.form.js的ajaxSubmit方法$("#button").click(function(){var hideForm = $("form"); var options = { dataType : "json", /*data: {"file": $("input[type=file]").val(), "username": "123", password: "123"},*/beforeSubmit : function() { alert("正在上传"); }, success : function(result) { alert("成功上传!"); }, error : function(result) { } }; hideForm.ajaxSubmit(options); }); 3. 在后台使用一个User对象接收username和password。<form action="fileUpload/fileUpload" method="post" enctype="multipart/form-data"><input type="file" name="file"><input type="submit" value="submit"></form>有可能你会按照下面的步骤做: 封装表单数据作为一个json对象, 给上面的js代码添加data
data:{"file": $("input[type=file]").val(), "user":{"username": "123", password: "123"}}在此处其实是画蛇添足,这种情况下发送的请求的详细情况如图:
此时页面会报错415。
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最合理的代码应该是:html代码与1相同, js代码与2相同, java代码
public String FileUpload1(@RequestParam("file")MultipartFile file, User user){ 而且User、前面不能加@RequestBody.。