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首页 / 脚本样式 / Ajax / 通过构造AJAX参数实现表单元素JSON相互转换

ajax提交服务器数据, 整理一下转换方法。

HTML:

<form id="fm" name="fm" action=""><input name="UserName" type="text" value="UserName1"/></form><input name="UserId" id="UserId" type="text" value="UserId1"/> 
1.表单元素转QueryString

var q = $("#fm,#UserId").serialize(); //q = UserName=UserName1&UserId=UserId1 
2.字符串, JSON 互相转换

var obj = jQuery.parseJSON("{"name":"John"}");alert( obj.name === "John" ); 
可以利用jquery-json插件实现转换,直接引用示例

var thing = {plugin: "jquery-json", version: 2.3};var encoded = $.toJSON( thing );// "{"plugin":"jquery-json","version":2.3}"var name = $.evalJSON( encoded ).plugin;// "jquery-json"var version = $.evalJSON(encoded).version;// 2.3 
3.表单,元素转Name,Value数组

var arr = $("#fm,#UserId").serializeArray();/*[ {name: "UserName", value: ""UserName"1"}, {name: "UserId", value: "UserId"}] */ 
4. 表单元素转JSON

$.fn.serializeObject = function(){var o = {};var a = this.serializeArray();$.each(a, function() {if (o[this.name] !== undefined) {if (!o[this.name].push) {o[this.name] = [o[this.name]];}o[this.name].push(this.value || "");} else {o[this.name] = this.value || "";}});return o;};var obj = $("form").serializeObject();/*obj: ObjectUserId: "UserId1"UserName: "UserName1"__proto__: Object*/ 
5. JSON2FORM

$.getJSON("url_to_file", function(data) {for (var i in data) {$("input[name=""+i+""]").val(data[i]);}}
Google过程中发现一个更强大的插件 http://code.google.com/p/jquery-load-json/

data = {"Name":"Emkay Entertainments","Address":"Nobel House, Regent Centre","Contact":"Phone"} $("div#data").loadJSON(data);<div id="data"><h1 id="Name">Emkay Entertainments</h1><label for="Address">Address:</label><span id="Address">Nobel House, Regent Centre</span> <label for="Contact">Contact by:</label><span id="Contact">Phone</span></div>