javascript自定义右键弹出菜单实现方法

本文实例讲述了javascript自定义右键弹出菜单实现方法。分享给大家供大家参考。具体实现方法如下：

<head runat="server"><title>无标题页</title><script type="text/javascript">var oPopup = window.createPopup（）;function PopMenu（id）{ var oPopBody = oPopup.document.body; oPopBody.style.backgroundColor = "buttonface"; oPopBody.style.border = "solid black 1px"; var TableBegin="<table style="border: 0; width: 100%; font-size: 12px;" cellpadding="0" cellspacing="0">"; var Tr1="<tr><td valign="middle" style="height: 20px;" onmousemove="this.bgColor="highlight";this.style.color="highlighttext"" onmouseout="this.bgColor="";this.style.color=""" onclick="parent.window.open（"/news/view.asp?id="+id+""）;">查看新闻</td></tr>"; var TrBr1="<tr><td style="background-color: ThreeDShadow; height: 1px;"></td></tr>"; var Tr2="<tr><td valign="middle" style="height: 20px;cursor:hand;" onmousemove="this.bgColor="highlight";this.style.color="highlighttext"" onmouseout="this.bgColor="";this.style.color=""" onclick="parent.document.frames["main"].location="divdiv.aspx?id="+id+";"">查看新闻</td></tr>"; var TableEnd="</table>"; oPopBody.innerHTML =TableBegin+Tr1+TrBr1+Tr2+TableEnd; oPopup.show（event.x, event.y, 90, 41, document.body）; return false;}</script></head><body> <form id="form1" runat="server"> <div><a href="javascript:void（0）;" oncontextmenu="PopMenu（1）;return false;"><img alt="" src="1.gif" style="border:0;width:150px;height:110px; cursor:hand"/><br/></a><iframe name="main" frameborder="0" width="100%" scrolling="auto" height="100%"></iframe> </div> </form></body></html>

希望本文所述对大家的javascript程序设计有所帮助。