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首页 / 脚本样式 / JavaScript / js变换显示图片的实例

开始界面如图:

复制代码 代码如下:
<head>
    <title></title>
   <script type="text/javascript">
       function UpdateImg() {
           //document.getElementById("img1").setAttribute("src", "images/2.jpg");
           var dogandcat = document.getElementsByName("dogandcat"); //获取所有name=dogandcat的单选按钮
           for (var i = 0; i < dogandcat.length; i++) {
               if (dogandcat[i].checked == true) {
                   var value = dogandcat[i].getAttribute("value");
                   switch (value) {
                       case "2":
                           document.getElementById("img1").setAttribute("src", "images/2.jpg");
                           break;
                       case "3":
                           document.getElementById("img1").setAttribute("src", "images/3.jpg");
                           break;
                       case "4":
                           document.getElementById("img1").setAttribute("src", "images/4.jpg");
                           break;
                       case "6":
                           document.getElementById("img1").setAttribute("src", "images/6.jpg");
                           break;
                   }
               }
           }
       }
    </script>

</head>
<body>
 <img id="img1" src="images/9.jpg" width="200px" height="200px" />
    <br />
    <input type="button"  value="改变图片" onclick="UpdateImg();" />
    <br />
    <input id="Radio1" name="dogandcat" type="radio" value="2" onclick="UpdateImg();"  />忧伤的小狗
    <input id="Radio2" name="dogandcat" type="radio" value="3" onclick="UpdateImg();"/>卖萌的小狗
    <input id="Radio3" name="dogandcat" type="radio" value="4" onclick="UpdateImg();"/>愤怒的小狗
    <input id="Radio4" name="dogandcat" type="radio" value="6" onclick="UpdateImg();"/>可爱的小猫
</body>

下面是程序运行时的界面:点击不同的按钮图片是不一样的