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首页 / 脚本样式 / JavaScript / 鼠标滑上去后图片放大浮出效果的js代码

复制代码 代码如下:
<script>
function GetAbsPosition(obj)
{
var curleft = 0, curtop = 0;
do {
curleft += obj.offsetLeft;
curtop += obj.offsetTop;
} while (obj = obj.offsetParent);
return [curleft,curtop];
}
function ShowFloatingImage(image, width, height)
{
var id = "trailimageid";
var newdiv = document.getElementById(id);
if(newdiv == null)
{
newdiv = document.createElement("div");
newdiv.setAttribute("id",id);
newdiv.setAttribute("onmouseout", "HideElement(""+id+"");");
document.body.appendChild(newdiv);
}
newdiv.innerHTML = "<img src="+image.src+ " width="+(image.width + width) + " height=" + (image.height + height) + " />";
var absPos = GetAbsPosition(image);
newdiv.style.position = "absolute";
newdiv.style.posLeft = absPos[0] - width/2;
newdiv.style.posTop = absPos[1] - height/2;
newdiv.style.display="block";
}
function HideElement(id)
{
var elem = document.getElementById(id);
elem.style.display="none";
}
</script>

例子:
复制代码 代码如下:
<body>
<img src="1.jpg" width="300" height="300" onmouseover="ShowFloatingImage(this, 150, 150);" />
</body>

经测试事件处理的不是很好。导致鼠标移开不能回到原位。