任意位置显示html菜单

脚本说明:

把如下代码加入<body>区域中

<SCRIPT language=javascript><！--

document.onclick = popUp



function popUp（） {

newX = window.event.x + document.body.scrollLeft

newY = window.event.y + document.body.scrollTop

menu = document.all.itemopen

  if （ menu.style.display == ""）{

    menu.style.display = "none" }

  else {

     menu.style.display = ""}

    menu.style.pixelLeft = newX - 50

    menu.style.pixelTop = newY - 50

}

//-->

</SCRIPT>

<！-- Start of Popup Menu  -->

<table id="itemopen" class="box"  style="display:none">

<tr><td><a href="index.htm" class="cc" >弹出菜单</a></td></tr>

<tr><td><a href="time1.htm" class="cc" >本站首页</a></td></tr>

<tr><td><a href="time2.htm" class="cc">My求职信</a></td></tr>

<tr><td><a href="time3.htm" class="cc" >网上赚钱</a></td></tr>

<tr><td><a href="ye1.htm" class="cc" >免费资源</a></td></tr>

<tr><td><a href="ye2.htm" class="cc" >更多连接</a></td></tr>

<tr><td><a href="ye3.htm" class="cc" >更多连接</a></td></tr>

<tr><td><a href="zh1.htm" class="cc" >更多连接</a></td></tr>

    </table>

  <！-- End of Popup Menu  -->