double sum = std::accumulate(std::begin(resultSet), std::end(resultSet), 0.0);double mean =sum / resultSet.size(); //均值 double accum= 0.0;std::for_each (std::begin(resultSet), std::end(resultSet), [&](const double d) {accum+= (d-mean)*(d-mean);}); double stdev = sqrt(accum/(resultSet.size()-1)); //方差作者:csdn博客 Spike_King