jquery实现ajax提交form表单的方法总结
方法一: 复制代码 代码如下:function AddHandlingFeeToRefund() { var AjaxURL= "../OrderManagement/AjaxModifyOrderService.aspx"; alert($("#formAddHandlingFee").serialize()); $.ajax({ type: "POST", dataType: "html", url: AjaxURL + "?Action=" + "...